Optimal. Leaf size=108 \[ \frac {4 \tanh ^{-1}(\cos (c+d x))}{a^4 d}-\frac {\cot (c+d x)}{a^4 d}-\frac {2 \cot (c+d x)}{5 a^4 d (1+\csc (c+d x))^3}+\frac {31 \cot (c+d x)}{15 a^4 d (1+\csc (c+d x))^2}-\frac {104 \cot (c+d x)}{15 a^4 d (1+\csc (c+d x))} \]
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Rubi [A]
time = 0.25, antiderivative size = 108, normalized size of antiderivative = 1.00, number of steps
used = 14, number of rules used = 8, integrand size = 21, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.381, Rules used = {2788, 3855,
3852, 8, 3862, 4007, 4004, 3879} \begin {gather*} -\frac {\cot (c+d x)}{a^4 d}+\frac {4 \tanh ^{-1}(\cos (c+d x))}{a^4 d}-\frac {104 \cot (c+d x)}{15 a^4 d (\csc (c+d x)+1)}+\frac {31 \cot (c+d x)}{15 a^4 d (\csc (c+d x)+1)^2}-\frac {2 \cot (c+d x)}{5 a^4 d (\csc (c+d x)+1)^3} \end {gather*}
Antiderivative was successfully verified.
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Rule 8
Rule 2788
Rule 3852
Rule 3855
Rule 3862
Rule 3879
Rule 4004
Rule 4007
Rubi steps
\begin {align*} \int \frac {\cot ^2(c+d x)}{(a+a \sin (c+d x))^4} \, dx &=\frac {\int \left (\frac {9}{a^2}-\frac {4 \csc (c+d x)}{a^2}+\frac {\csc ^2(c+d x)}{a^2}-\frac {2}{a^2 (1+\csc (c+d x))^3}+\frac {9}{a^2 (1+\csc (c+d x))^2}-\frac {16}{a^2 (1+\csc (c+d x))}\right ) \, dx}{a^2}\\ &=\frac {9 x}{a^4}+\frac {\int \csc ^2(c+d x) \, dx}{a^4}-\frac {2 \int \frac {1}{(1+\csc (c+d x))^3} \, dx}{a^4}-\frac {4 \int \csc (c+d x) \, dx}{a^4}+\frac {9 \int \frac {1}{(1+\csc (c+d x))^2} \, dx}{a^4}-\frac {16 \int \frac {1}{1+\csc (c+d x)} \, dx}{a^4}\\ &=\frac {9 x}{a^4}+\frac {4 \tanh ^{-1}(\cos (c+d x))}{a^4 d}-\frac {2 \cot (c+d x)}{5 a^4 d (1+\csc (c+d x))^3}+\frac {3 \cot (c+d x)}{a^4 d (1+\csc (c+d x))^2}-\frac {16 \cot (c+d x)}{a^4 d (1+\csc (c+d x))}+\frac {2 \int \frac {-5+2 \csc (c+d x)}{(1+\csc (c+d x))^2} \, dx}{5 a^4}-\frac {3 \int \frac {-3+\csc (c+d x)}{1+\csc (c+d x)} \, dx}{a^4}+\frac {16 \int -1 \, dx}{a^4}-\frac {\text {Subst}(\int 1 \, dx,x,\cot (c+d x))}{a^4 d}\\ &=\frac {2 x}{a^4}+\frac {4 \tanh ^{-1}(\cos (c+d x))}{a^4 d}-\frac {\cot (c+d x)}{a^4 d}-\frac {2 \cot (c+d x)}{5 a^4 d (1+\csc (c+d x))^3}+\frac {31 \cot (c+d x)}{15 a^4 d (1+\csc (c+d x))^2}-\frac {16 \cot (c+d x)}{a^4 d (1+\csc (c+d x))}-\frac {2 \int \frac {15-7 \csc (c+d x)}{1+\csc (c+d x)} \, dx}{15 a^4}-\frac {12 \int \frac {\csc (c+d x)}{1+\csc (c+d x)} \, dx}{a^4}\\ &=\frac {4 \tanh ^{-1}(\cos (c+d x))}{a^4 d}-\frac {\cot (c+d x)}{a^4 d}-\frac {2 \cot (c+d x)}{5 a^4 d (1+\csc (c+d x))^3}+\frac {31 \cot (c+d x)}{15 a^4 d (1+\csc (c+d x))^2}-\frac {4 \cot (c+d x)}{a^4 d (1+\csc (c+d x))}+\frac {44 \int \frac {\csc (c+d x)}{1+\csc (c+d x)} \, dx}{15 a^4}\\ &=\frac {4 \tanh ^{-1}(\cos (c+d x))}{a^4 d}-\frac {\cot (c+d x)}{a^4 d}-\frac {2 \cot (c+d x)}{5 a^4 d (1+\csc (c+d x))^3}+\frac {31 \cot (c+d x)}{15 a^4 d (1+\csc (c+d x))^2}-\frac {104 \cot (c+d x)}{15 a^4 d (1+\csc (c+d x))}\\ \end {align*}
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Mathematica [B] Leaf count is larger than twice the leaf count of optimal. \(315\) vs. \(2(108)=216\).
time = 0.28, size = 315, normalized size = 2.92 \begin {gather*} \frac {\left (\cos \left (\frac {1}{2} (c+d x)\right )+\sin \left (\frac {1}{2} (c+d x)\right )\right )^3 \left (24 \sin \left (\frac {1}{2} (c+d x)\right )-12 \left (\cos \left (\frac {1}{2} (c+d x)\right )+\sin \left (\frac {1}{2} (c+d x)\right )\right )+76 \sin \left (\frac {1}{2} (c+d x)\right ) \left (\cos \left (\frac {1}{2} (c+d x)\right )+\sin \left (\frac {1}{2} (c+d x)\right )\right )^2-38 \left (\cos \left (\frac {1}{2} (c+d x)\right )+\sin \left (\frac {1}{2} (c+d x)\right )\right )^3+316 \sin \left (\frac {1}{2} (c+d x)\right ) \left (\cos \left (\frac {1}{2} (c+d x)\right )+\sin \left (\frac {1}{2} (c+d x)\right )\right )^4-15 \cot \left (\frac {1}{2} (c+d x)\right ) \left (\cos \left (\frac {1}{2} (c+d x)\right )+\sin \left (\frac {1}{2} (c+d x)\right )\right )^5+120 \log \left (\cos \left (\frac {1}{2} (c+d x)\right )\right ) \left (\cos \left (\frac {1}{2} (c+d x)\right )+\sin \left (\frac {1}{2} (c+d x)\right )\right )^5-120 \log \left (\sin \left (\frac {1}{2} (c+d x)\right )\right ) \left (\cos \left (\frac {1}{2} (c+d x)\right )+\sin \left (\frac {1}{2} (c+d x)\right )\right )^5+15 \left (\cos \left (\frac {1}{2} (c+d x)\right )+\sin \left (\frac {1}{2} (c+d x)\right )\right )^5 \tan \left (\frac {1}{2} (c+d x)\right )\right )}{30 d (a+a \sin (c+d x))^4} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.31, size = 119, normalized size = 1.10
method | result | size |
derivativedivides | \(\frac {\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-\frac {32}{5 \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{5}}+\frac {16}{\left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{4}}-\frac {88}{3 \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{3}}+\frac {28}{\left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{2}}-\frac {36}{\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1}-\frac {1}{\tan \left (\frac {d x}{2}+\frac {c}{2}\right )}-8 \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{2 d \,a^{4}}\) | \(119\) |
default | \(\frac {\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-\frac {32}{5 \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{5}}+\frac {16}{\left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{4}}-\frac {88}{3 \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{3}}+\frac {28}{\left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{2}}-\frac {36}{\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1}-\frac {1}{\tan \left (\frac {d x}{2}+\frac {c}{2}\right )}-8 \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{2 d \,a^{4}}\) | \(119\) |
risch | \(-\frac {4 \left (-320 \,{\mathrm e}^{4 i \left (d x +c \right )}+150 i {\mathrm e}^{5 i \left (d x +c \right )}+367 \,{\mathrm e}^{2 i \left (d x +c \right )}-385 i {\mathrm e}^{3 i \left (d x +c \right )}-47+205 i {\mathrm e}^{i \left (d x +c \right )}+30 \,{\mathrm e}^{6 i \left (d x +c \right )}\right )}{15 \left ({\mathrm e}^{2 i \left (d x +c \right )}-1\right ) \left ({\mathrm e}^{i \left (d x +c \right )}+i\right )^{5} d \,a^{4}}-\frac {4 \ln \left ({\mathrm e}^{i \left (d x +c \right )}-1\right )}{a^{4} d}+\frac {4 \ln \left ({\mathrm e}^{i \left (d x +c \right )}+1\right )}{a^{4} d}\) | \(148\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] Leaf count of result is larger than twice the leaf count of optimal. 288 vs.
\(2 (102) = 204\).
time = 0.30, size = 288, normalized size = 2.67 \begin {gather*} -\frac {\frac {\frac {491 \, \sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} + \frac {1690 \, \sin \left (d x + c\right )^{2}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{2}} + \frac {2570 \, \sin \left (d x + c\right )^{3}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{3}} + \frac {1815 \, \sin \left (d x + c\right )^{4}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{4}} + \frac {555 \, \sin \left (d x + c\right )^{5}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{5}} + 15}{\frac {a^{4} \sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} + \frac {5 \, a^{4} \sin \left (d x + c\right )^{2}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{2}} + \frac {10 \, a^{4} \sin \left (d x + c\right )^{3}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{3}} + \frac {10 \, a^{4} \sin \left (d x + c\right )^{4}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{4}} + \frac {5 \, a^{4} \sin \left (d x + c\right )^{5}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{5}} + \frac {a^{4} \sin \left (d x + c\right )^{6}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{6}}} + \frac {120 \, \log \left (\frac {\sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1}\right )}{a^{4}} - \frac {15 \, \sin \left (d x + c\right )}{a^{4} {\left (\cos \left (d x + c\right ) + 1\right )}}}{30 \, d} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] Leaf count of result is larger than twice the leaf count of optimal. 369 vs.
\(2 (102) = 204\).
time = 0.37, size = 369, normalized size = 3.42 \begin {gather*} \frac {94 \, \cos \left (d x + c\right )^{4} + 222 \, \cos \left (d x + c\right )^{3} - 115 \, \cos \left (d x + c\right )^{2} + 30 \, {\left (\cos \left (d x + c\right )^{4} - 2 \, \cos \left (d x + c\right )^{3} - 5 \, \cos \left (d x + c\right )^{2} - {\left (\cos \left (d x + c\right )^{3} + 3 \, \cos \left (d x + c\right )^{2} - 2 \, \cos \left (d x + c\right ) - 4\right )} \sin \left (d x + c\right ) + 2 \, \cos \left (d x + c\right ) + 4\right )} \log \left (\frac {1}{2} \, \cos \left (d x + c\right ) + \frac {1}{2}\right ) - 30 \, {\left (\cos \left (d x + c\right )^{4} - 2 \, \cos \left (d x + c\right )^{3} - 5 \, \cos \left (d x + c\right )^{2} - {\left (\cos \left (d x + c\right )^{3} + 3 \, \cos \left (d x + c\right )^{2} - 2 \, \cos \left (d x + c\right ) - 4\right )} \sin \left (d x + c\right ) + 2 \, \cos \left (d x + c\right ) + 4\right )} \log \left (-\frac {1}{2} \, \cos \left (d x + c\right ) + \frac {1}{2}\right ) + {\left (94 \, \cos \left (d x + c\right )^{3} - 128 \, \cos \left (d x + c\right )^{2} - 243 \, \cos \left (d x + c\right ) - 6\right )} \sin \left (d x + c\right ) - 237 \, \cos \left (d x + c\right ) + 6}{15 \, {\left (a^{4} d \cos \left (d x + c\right )^{4} - 2 \, a^{4} d \cos \left (d x + c\right )^{3} - 5 \, a^{4} d \cos \left (d x + c\right )^{2} + 2 \, a^{4} d \cos \left (d x + c\right ) + 4 \, a^{4} d - {\left (a^{4} d \cos \left (d x + c\right )^{3} + 3 \, a^{4} d \cos \left (d x + c\right )^{2} - 2 \, a^{4} d \cos \left (d x + c\right ) - 4 \, a^{4} d\right )} \sin \left (d x + c\right )\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \frac {\int \frac {\cot ^{2}{\left (c + d x \right )}}{\sin ^{4}{\left (c + d x \right )} + 4 \sin ^{3}{\left (c + d x \right )} + 6 \sin ^{2}{\left (c + d x \right )} + 4 \sin {\left (c + d x \right )} + 1}\, dx}{a^{4}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 7.34, size = 135, normalized size = 1.25 \begin {gather*} -\frac {\frac {120 \, \log \left ({\left | \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) \right |}\right )}{a^{4}} - \frac {15 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )}{a^{4}} - \frac {15 \, {\left (8 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 1\right )}}{a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )} + \frac {4 \, {\left (135 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} + 435 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 605 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 385 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 104\right )}}{a^{4} {\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 1\right )}^{5}}}{30 \, d} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 12.05, size = 203, normalized size = 1.88 \begin {gather*} \frac {\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}{2\,a^4\,d}-\frac {37\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^5+121\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4+\frac {514\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3}{3}+\frac {338\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2}{3}+\frac {491\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}{15}+1}{d\,\left (2\,a^4\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^6+10\,a^4\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^5+20\,a^4\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4+20\,a^4\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3+10\,a^4\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2+2\,a^4\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\right )}-\frac {4\,\ln \left (\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\right )}{a^4\,d} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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